x^2-8x+14.75=0

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Solution for x^2-8x+14.75=0 equation: 



x^2-8x+14.75=0

a = 1; b = -8; c = +14.75;
Δ = b2-4ac
Δ = -82-4·1·14.75
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{5}}{2*1}=\frac{8-\sqrt{5}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{5}}{2*1}=\frac{8+\sqrt{5}}{2}
$

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